said: The methyl group is an activating group/ortho-para director, while the iodine group is a deactivating group/ortho-para director. Activating groups direct over deactivating groups, so the bromine would add either ortho or para compared to the methyl group. Since para is usually more stable, adding the bromine to this location on the ring would be most preferred, making the major product 5-bromo-1-iodo-2-methylcyclohexene
accurate portrayal of how i try to show my affection
said: I have a question. If I'm going to perform an electrophilic aromatic substitution reaction on 1-iodo-2-methylcyclohexane using Br2 in a solution of AlBr3, then will the major product have the electrophile add in the ortho, para, or meta position and of which substituent is this relative too? Why?
aaaaaaaah we can have a study date tomorrow 0u0
alrighty!! i’m not sure when i’ll be free since i was hoping to go into town tomorrow if the roads aren’t awful and my brother will be coming back for break so i might have to help him haul stuff in… but at some point, definitely!!
my next exam is just a bunch of calculating moles and molecules and atoms, so if you want to expand i will definitely not be upset…!!!! ;v;
hmmm. i think that would be easiest done through skype using screenshare or on livestream or something? i could grab my tablet and try to expand, since that’s a little trickier.
god fucking bless you bee i love you so much thank you im so sorry im so unlearned ;u;
no problem! i can expand a little more if need be, or help you if you have any other questions or anything, too! i adore chemistry and i still have all of my old notes to look back on because i’m a nerd uvu
i still have my gen chem and ap chem notebooks, actually… i took some pretty good notes, too, and i believe i still have practice problems and solutions tucked away somewhere.